Difference between revisions of "Talk:LED Lighting"
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(Base flat; 3 V 330 R) |
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Memory tells me that, for cylindrical LEDs as in the diagram, the flat on the base indicates negative. I imagine that applying 3 volts through 330 ohms would be a suitable test. [[User:John Stockton|John Stockton]] ([[User talk:John Stockton|talk]]) 09:42, 18 October 2015 (BST) | Memory tells me that, for cylindrical LEDs as in the diagram, the flat on the base indicates negative. I imagine that applying 3 volts through 330 ohms would be a suitable test. [[User:John Stockton|John Stockton]] ([[User talk:John Stockton|talk]]) 09:42, 18 October 2015 (BST) | ||
| + | : Yup the flat is typically -ve, and the positive is nearly always the longer lead IME (in spite of what the article claims). Note that You may need more than 3V to light blue LEDs... --[[User:John Rumm|John Rumm]] ([[User talk:John Rumm|talk]]) 18:43, 18 October 2015 (BST) | ||
Revision as of 17:43, 18 October 2015
Polarity
Memory tells me that, for cylindrical LEDs as in the diagram, the flat on the base indicates negative. I imagine that applying 3 volts through 330 ohms would be a suitable test. John Stockton (talk) 09:42, 18 October 2015 (BST)