Talk:LED Lighting

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Revision as of 17:43, 18 October 2015 by John Rumm (talk | contribs)
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Polarity

Memory tells me that, for cylindrical LEDs as in the diagram, the flat on the base indicates negative. I imagine that applying 3 volts through 330 ohms would be a suitable test. John Stockton (talk) 09:42, 18 October 2015 (BST)

Yup the flat is typically -ve, and the positive is nearly always the longer lead IME (in spite of what the article claims). Note that You may need more than 3V to light blue LEDs... --John Rumm (talk) 18:43, 18 October 2015 (BST)